Matematika :

Oct 19, 2011

Problem Catur : Alexander Beliavsky

a) 
Beliavsky vs Jan Ristoja, Tallinn, 1968
[ Nd6 if Rd8 Nxc8 & Bh3 ]

b) 
Beliavsky vs Miguel Quinteros, Las Palmas, 1974
[ Rxd8+ ]

c) 
Beliavsky vs Lev Alburt, Yerevan, 1975
[ g4 if Qf6 Bg5 ]

d) 
Beliavsky vs Eduard Gufeld, Novosibirsk, 1976
[ Rxg7+ Kxg7 Nf5+ ]

e) 
Beliavsky vs Arshak Petrosian, Baku, 1977
Bc5 if Rd8 e4 Nb6 Rg4 Qh6 Be3 ]


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